A) 125 m
B) 50 m
C) 100 m
D) 150 m
Correct Answer: A
Solution :
\[T=\frac{2u\sin \theta }{g}=10\sec \Rightarrow u\sin \theta =50\ m/s\] \ \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}=\frac{{{(u\sin \theta )}^{2}}}{2g}=\frac{50\times 50}{2\times 10}=125m\]You need to login to perform this action.
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