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JEE Main & Advanced Physics Question Bank Oblique Projectile Motion

  • question_answer
    A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of \[{{30}^{o}}\] with the horizontal. The change in momentum (in magnitude) of the body is              [MP PET 1997]

    A)             \[24.5\,N-s\]

    B)             \[49.0\,N-s\]

    C)             \[98.0\,N-s\]

    D)               \[50.0\,N-s\]

    Correct Answer: B

    Solution :

                    Change in momentum = \[2mu\sin \theta \]       =\[2\times 0.5\times 98\times \sin 30\]=\[45N\text{-}s\]


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