A) \[{{\cos }^{-1}}\left( \frac{{{V}^{2}}}{Rg} \right)\]
B) \[{{\cos }^{-1}}\left( \frac{gR}{{{V}^{2}}} \right)\]
C) \[\frac{1}{2}\left( \frac{{{V}^{2}}}{Rg} \right)\]
D) \[\frac{1}{2}{{\sin }^{-1}}\left( \frac{gR}{{{V}^{2}}} \right)\]
Correct Answer: D
Solution :
\[R=\frac{{{v}^{2}}\sin 2\theta }{g}\] Þ \[\theta =\frac{1}{2}{{\sin }^{-1}}\left( \frac{gR}{{{v}^{2}}} \right)\]
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