JEE Main & Advanced Physics Question Bank Oblique Projectile Motion

  • question_answer
    A particle covers 50 m distance when projected with an initial speed.  On the same surface it will cover a distance, when projected with double the initial speed   [RPMT 2000]

    A)             100 m

    B)               150 m

    C)             200 m 

    D)             250 m

    Correct Answer: C

    Solution :

                    \[R=\frac{{{u}^{2}}\sin 2\theta }{g}=R\propto {{u}^{2}}.\]So if the speed of projection doubled, the range will becomes four times,             i.e., \[4\times 50=200\,m\]


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