A) 100 m
B) 200 m
C) 400 m
D) 800 m
Correct Answer: B
Solution :
\[{{R}_{\max }}=\frac{{{u}^{2}}}{g}\]\[=400m\] \[(\text{For }\theta =45{}^\circ )\] \[{{H}_{\max }}=\frac{{{u}^{2}}}{2g}=\frac{400}{2}=200m\] \[(\text{For }\theta =90{}^\circ )\]You need to login to perform this action.
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