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JEE Main & Advanced Physics Question Bank Oblique Projectile Motion

  • question_answer
    The angle of projection at which the horizontal range and maximum height of projectile are equal is [Kurukshetra CEE 1996; BCECE 2003; Pb. PET 2001]

    A)             \[{{45}^{o}}\]         

    B)             \[\theta ={{\tan }^{-1}}(0.25)\]

    C)             \[\theta ={{\tan }^{-1}}4\]or \[(\theta =76{}^\circ )\]      

    D)             \[{{60}^{o}}\]

    Correct Answer: C

    Solution :

                    \[R=4H\cot \theta .\]             When \[R=H\] then \[\cot \theta =1/4\]\[\Rightarrow \theta ={{\tan }^{-1}}(4)\]


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