A) \[{{U}_{vertical}}\]
B) \[{{U}_{horizontal}}\]
C) \[U={{U}^{2}}_{vertical}+{{U}^{2}}_{horizontal}\]
D) \[U=U\,{{({{U}^{2}}_{vertical}+{{U}^{2}}_{horizontal})}^{1/2}}\]
Correct Answer: A
Solution :
Time of flight = \[\frac{2u\sin \theta }{g}=\frac{2{{u}_{y}}}{g}=\frac{2\times {{u}_{\text{vertical}}}}{g}\]
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