JEE Main & Advanced Physics Question Bank Oblique Projectile Motion

  • question_answer
    The horizontal range of a projectile is \[4\sqrt{3}\] times its maximum height. Its angle of projection will be [J & K CET 2004; DPMT 2003]

    A)             \[{{45}^{o}}\]         

    B)           \[{{60}^{o}}\]

    C)             \[{{90}^{o}}\]         

    D)             \[{{30}^{o}}\]

    Correct Answer: D

    Solution :

                    \[R=4H\cot \theta ,\]if R =\[4\sqrt{3}H\]then \[\cot \theta =\sqrt{3}\]Þ \[\theta =30{}^\circ \]


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