JEE Main & Advanced Mathematics Probability Question Bank Odds in favour and odds against Addition theorem on probability

  • question_answer
    A card is drawn at random from a pack of cards. The probability of this card being a red or a queen is [MP PET 1989]

    A)                                                                                            \[\frac{1}{13}\]                                                                                          

    B)                                                                                            \[\frac{1}{26}\]

    C)                                                                                             \[\frac{1}{2}\]                                                                                           

    D)                                                                                            \[\frac{7}{13}\]

    Correct Answer: D

    Solution :

                       Required probability  is                                                                                                         \[P(\text{Red}+\text{Queen})-P(\text{Red}\cap \text{Queen})\]                                                                                                                                                                                                                                                               \[=P(\text{Red})+P(\text{Queen})-P(\text{Red}\cap \text{Queen})\]                                                                                                                                                                                                                                                      \[=\frac{26}{52}+\frac{4}{52}-\frac{2}{52}=\frac{28}{52}=\frac{7}{13}.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner