A) \[\frac{1}{20}\]
B) \[\frac{9}{20}\]
C) \[\frac{11}{20}\]
D) \[\frac{19}{20}\]
Correct Answer: B
Solution :
\[P(A\cup B)=P(A)+P(B)=\frac{1}{4}+\frac{1}{5}=\frac{9}{20}.\] {Since events are mutually exclusive, so \[P(A\cap B)=0\}\]
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