A) 0.4
B) 0.8
C) 1.2
D) 1.4
Correct Answer: C
Solution :
We are given that \[P(A\cup B)=0.6\] and \[P(A\cap B)=0.2\] . We know that if \[A\] and \[B\] are any two events, then \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] \[0.6=1-P(\bar{A})+1-P(\bar{B})-0.2\] \[\Rightarrow P(\bar{A})+P(\bar{B})=2-0.8=1.2\].You need to login to perform this action.
You will be redirected in
3 sec