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JEE Main & Advanced Mathematics Probability Question Bank Odds in favour and odds against Addition theorem on probability

  • question_answer
    Twelve tickets are numbered 1 to 12. One ticket is drawn at random, then the probability of the number to be divisible by 2 or 3, is

    A)                 \[\frac{2}{3}\]       

    B)                 \[\frac{7}{12}\]

    C)                 \[\frac{5}{6}\]       

    D)                 \[\frac{3}{4}\]

    Correct Answer: A

    Solution :

                       \[P(2\cup 3)=P(2)+P(3)-P(2\cap 3)\]                                                 \[=\frac{6}{12}+\frac{4}{12}-\frac{2}{12}=\frac{2}{3}.\]


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