JEE Main & Advanced Mathematics Probability Question Bank Odds in favour and odds against Addition theorem on probability

  • question_answer
    The probability of solving a question by three students are \[\frac{1}{2},\,\,\frac{1}{4},\,\,\frac{1}{6}\] respectively. Probability of question is being solved will be                                          [UPSEAT 1999]

    A)                 \[\frac{33}{48}\]  

    B)                 \[\frac{35}{48}\]

    C)                 \[\frac{31}{48}\]  

    D)                 \[\frac{37}{48}\]

    Correct Answer: A

    Solution :

                       (i) This question can also be solved by one student                    (ii) This question can be solved by two students simultaneously                    (ii) This question can be solved by three students all together.                    \[P(A)=\frac{1}{2},\,\,P(B)=\frac{1}{4},\,P(C)=\frac{1}{6}\]                    \[P(A\cup B\cup C)=\] \[P(A)\,+P(B)+P(C)\]                    \[-[P(A).\,P(B)+P(B)\,.\,P(C)+\,P(C)\,.\,P(A)]+[P(A).P(B).P(C)]\]                                 \[=\frac{1}{2}+\frac{1}{4}+\frac{1}{6}-\left[ \frac{1}{2}\times \frac{1}{4}+\frac{1}{4}\times \frac{1}{6}+\frac{1}{6}\times \frac{1}{2} \right]+\left[ \frac{1}{2}\times \frac{1}{4}\times \frac{1}{6} \right]=\frac{33}{48}\].


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