A) \[\frac{1}{26}\]
B) \[\frac{3}{26}\]
C) \[\frac{4}{13}\]
D) \[\frac{3}{13}\]
Correct Answer: C
Solution :
Probability of king \[P(A)=\frac{4}{52}=\frac{1}{13}\] Probability of spade \[=\frac{13}{52}\] \[=\frac{1}{4}\] \ \[P\](King or spade) = \[P(\]king) + P (spade)\[-P\](King and spade) \[=\frac{1}{13}+\frac{1}{4}-\frac{1}{52}\]\[=\frac{4+13-1}{52}=\frac{16}{52}=\frac{4}{13}\].You need to login to perform this action.
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