A) Independent
B) Mutually exclusive
C) Mutually exhaustive
D) Dependent
Correct Answer: B
Solution :
\[P(A{{}^{c}})=1-P(A)\] \[\Rightarrow \] \[P(A)=\frac{1}{6}\] Now \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] Þ \[\frac{5}{6}=\frac{1}{6}+\frac{2}{3}-P(A\cap B)\] Þ \[P(A\cap B)=0\] Hence, events A and B are mutually exclusive.You need to login to perform this action.
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