A) \[{{2}^{n}}\]
B) \[{{n}^{2}}\]
C) 1/n
D) \[1/{{2}^{n}}\]
Correct Answer: D
Solution :
Ways of selection two subset of \[A={{({{2}^{n}})}^{2}}\] Ways of selection \[A\cup B\] and \[A\cap B\] are \[{{2}^{n}}\] \Required probability \[=\frac{\text{favourable cases}}{\text{total cases}}=\frac{{{2}^{n}}}{{{({{2}^{n}})}^{2}}}=\frac{1}{{{2}^{n}}}\].
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