JEE Main & Advanced Mathematics Probability Question Bank Odds in favour and odds against Addition theorem on probability

  • question_answer
    The odds against a certain event is 5 : 2 and the odds in favour of another event is  6 : 5. If both the events are independent, then the probability that at least one of the events will happen is                                  [RPET 1997]

    A)                                                                                           \[\frac{50}{77}\]                                                                                        

    B)                                                                                           \[\frac{52}{77}\]

    C)                                                                                           \[\frac{25}{88}\]                                                                                        

    D)                                                                                           \[\frac{63}{88}\]

    Correct Answer: B

    Solution :

                       Let                                                                                                     \[A\]  and                                                                                                     \[B\]  be two given events. The odds against                                                                                                     \[A\]  are \[5:2\], therefore                                                                                       \[P(A)=\frac{2}{7}\] .                    The odds in favour of                                                                                                     \[B\]  are \[6:5\],                    therefore                                                                                      \[P(B)=\frac{6}{11}.\]                    The required probability                                                                                \[=1-P(\bar{A})\,P(\bar{B})\]                                                                                                                    \[=1-\left( 1-\frac{2}{7} \right)\,\left( 1-\frac{6}{11} \right)=\frac{52}{77}.\]


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