A) 2, 2
B) 2, 3
C) 2, 1
D) None of these
Correct Answer: A
Solution :
\[\rho .\frac{{{d}^{2}}y}{d{{x}^{2}}}={{\left[ 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right]}^{3/2}}\]Þ \[{{\left( \rho .\frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{2}}={{\left[ 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right]}^{3}}\] order = 2, degree = 2.You need to login to perform this action.
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