A) 1 : 2
B) 2 : 3
C) 3 : 4
D) 4 : 5
Correct Answer: C
Solution :
If is given that First over tone of closed pipe = First over tone of open pipe Þ \[3\left( \frac{v}{4{{l}_{1}}} \right)=2\left( \frac{v}{2{{l}_{2}}} \right)\]; where l1 and l2 are the lengths of closed and open organ pipes hence \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{3}{4}\]You need to login to perform this action.
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