A) First
B) Second
C) Third
D) Fourth
Correct Answer: A
Solution :
Fundamental frequency of open pipe \[{{n}_{1}}=\frac{v}{2l}=\frac{330}{2\times 0.3}=550\]\[Hz\] First harmonic = \[2\times {{n}_{1}}=1100\]\[Hz\]. = \[1.1\,\,kHz\]You need to login to perform this action.
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