A) 1.5
B) 0.75
C) 2
D) 1
Correct Answer: B
Solution :
First tone of open pipe = first overtone of closed pipe Þ\[\frac{v}{2{{l}_{0}}}=\frac{3v}{4{{l}_{c}}}\]Þ \[{{l}_{c}}=\frac{3\times 2\times 0.5}{4}=0.75m\]You need to login to perform this action.
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