A) 500
B) 300
C) 330
D) 165
Correct Answer: A
Solution :
For closed pipe \[{{l}_{1}}=\frac{v}{4n}\];\[{{l}_{2}}=\frac{3v}{4n}\]Þ\[v=2n\,({{l}_{2}}-{{l}_{1}})\] Þ \[n=\frac{v}{2({{l}_{2}}-{{l}_{1}})}=\frac{330}{2\times (0.49-0.16)}=500\,Hz\]You need to login to perform this action.
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