Answer:
Clearly, \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=-\alpha x\] or \[a=-ax\] Time period, \[T=2\pi \sqrt{\frac{x}{a}}=2\pi \sqrt{\frac{x}{\alpha x}}=\frac{2\pi }{\sqrt{\alpha }}\]
You need to login to perform this action.
You will be redirected in
3 sec