Answer:
\[\frac{\text{Potential energy}}{\text{Total energy}}=\frac{\frac{1}{2}m{{\omega }^{2}}{{y}^{2}}}{\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}}\] \[\frac{{{y}^{2}}}{{{a}^{2}}}=\frac{{{(a/2)}^{2}}}{{{a}^{2}}}=\frac{1}{4}\mathbf{1:4}\]
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