Answer:
Force constant, \[k=\frac{F}{x}\] The length of longer part is\[2x\text{ }/\text{3}\]. So its force constant is \[k'=\frac{F}{2x/3}=\frac{3}{2}\frac{F}{x}=\frac{\mathbf{3}}{\mathbf{2}}\mathbf{k}\].
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