Answer:
\[{{\upsilon }_{\max }}=\omega A=\frac{2\pi }{T}A\] \[\therefore \] \[T=\frac{2\pi A}{{{\upsilon }_{\max }}}\] \[=\frac{2\times 22\times 7\times {{10}^{-3}}}{7\times 4.4}=\mathbf{0}\mathbf{.01s}.\]
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