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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Osmosis and Osmotic pressure of the solution

  • question_answer
    A 5% solution of canesugar (mol. wt. =342) is isotonic with 1% solution of a substance \[X\]. The molecular weight of \[X\]  is                          [CBSE PMT 1998]

    A)                 34.2       

    B)                 171.2

    C)                 68.4       

    D)                 136.8

    Correct Answer: C

    Solution :

             Molar concentration of cane sugar \[=\frac{5}{342}\times \frac{1000}{100}=\frac{50}{342}\]            Molar concentration of  X = \[\frac{1}{m}\times \frac{1000}{100}=\frac{10}{m}\]                 \[\frac{10}{m}=\frac{50}{342}\] or \[m=68.4\].


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