A) 0
B) 6
C) 4
D) 3
Correct Answer: A
Solution :
\[\overset{+6}{\mathop{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}}\,\to \overset{+6}{\mathop{{{K}_{2}}Cr{{O}_{4}}}}\,\].In this reaction no change in oxidation state of chromium.
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