A) \[MnO_{4}^{-}\to \,M{{n}^{2+}}\]
B) \[CrO_{4}^{2}\to \,C{{r}^{3+}}\]
C) \[MnO_{4}^{2-}\to \,Mn{{O}_{2}}\]
D) \[C{{r}_{2}}O_{7}^{2-}\,\to \,2C{{r}^{3+}}\]
Correct Answer: A
Solution :
\[MnO_{4}^{-}\to M{{n}^{2+}}+5{{e}^{-}}\].
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