JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation number and Oxidation state

  • question_answer
    The oxidation number and the electronic configuration of sulphur in \[{{H}_{2}}S{{O}_{4}}\]is     [KCET 2002]

    A)                 + 4;\[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}\]  

    B)                 + 2; \[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{2}}\]

    C)                 + 3; \[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{1}}\]

    D)                 + 6; \[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}\]

    Correct Answer: D

    Solution :

           \[{{H}_{2}}\overset{*\,\,\,\,\,\,}{\mathop{S{{O}_{4}}}}\,\]            \[2\times (+1)+x+4\times (-2)=0\]            \[+2+x-8=0\];  \[x=8-2=+6\]            Electronic configuration of sulphur in \[{{H}_{2}}S{{O}_{4}}\] is                                 \[1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{6}}\].


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