A) In neutral solution
B) In acidic solution
C) In non-polar solvent
D) In alkaline solution
Correct Answer: B
Solution :
When \[{{H}_{2}}{{O}_{2}}\] reduces with \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]. It is present in acidic solution. \[2{{K}_{4}}[Fe{{(CN)}_{6}}+{{H}_{2}}S{{O}_{4}}+{{H}_{2}}{{O}_{2}}\to \] \[2{{K}_{3}}[Fe{{(CN)}_{6}}]+{{K}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]You need to login to perform this action.
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