A) Oxidation by 3 electrons
B) Reduction by 3 electrons
C) Oxidation by 5 electrons
D) Reduction by 5 electrons
Correct Answer: D
Solution :
\[MnO_{4}^{-}\to M{{n}^{2+}}\]. In this reaction \[5{{e}^{-}}\]are needed for the reduction of \[M{{n}^{2+}}\] as: \[MnO_{4}^{-}+5{{e}^{-}}\to M{{n}^{2+}}\].You need to login to perform this action.
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