A) Zinc ions
B) Iodide ions
C) Zinc atom
D) Iodine
Correct Answer: C
Solution :
\[\overset{o}{\mathop{Zn}}\,+\overset{o}{\mathop{{{I}_{2}}}}\,\to \overset{+2\,\,-1\,\,\,}{\mathop{Zn{{I}_{2}}}}\,\] In this reaction \[Zn\]atom oxidised to \[\overset{{}}{\mathop{Z{{n}^{2+}}}}\,\] ion and iodine reduced to \[{{I}^{-}}\].You need to login to perform this action.
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