A) \[{{C}_{2}}O_{4}^{2-}\]
B) \[MnO_{4}^{-}\]
C) \[M{{n}^{2+}}\]
D) \[{{H}^{+}}\]
Correct Answer: A
Solution :
\[{{C}_{2}}O_{4}^{2-}+MnO_{4}^{-}+{{H}^{+}}\to M{{n}^{2+}}+C{{O}_{2}}+{{H}_{2}}O\]. In this reaction \[{{C}_{2}}O_{4}^{2-}\] act as a reducing agent.
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