A) \[NO_{2}^{+}\] and \[Ba{{O}_{2}}\]
B) \[K{{O}_{2}}\] and \[Ba{{O}_{2}}\]
C) \[K{{O}_{2}}\] only
D) \[Ba{{O}_{2}}\] only
Correct Answer: C
Solution :
\[K{{O}_{2}}\] because in \[O_{2}^{-}\] (superoxide ion) One unpaired electron is present in the antibonding orbital.You need to login to perform this action.
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