A) 63
B) 36
C) 24
D) 40
Correct Answer: B
Solution :
Let the digit at unit place be x and the digit at tens place be y, then the number \[=10y+x\] Now, according to the question, \[\frac{10y+x}{y+x}=\frac{4}{1}\] \[\Rightarrow \] \[10y+x=4y+4x\] \[\Rightarrow \] \[6y=3x\] \[\Rightarrow \] \[x=2y\] .....(1) Also, \[x=3+y\] \[\Rightarrow \] \[2y=3+y\] [From (1)] \[\Rightarrow \] \[y=3\]and \[x=6\] \[\therefore \]Number = 36You need to login to perform this action.
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