A) \[4\sqrt{2}\]
B) \[2\sqrt{2}\]
C) 8
D) \[8\sqrt{2}\]
Correct Answer: D
Solution :
Clearly; \[a=\left| \frac{-8}{\sqrt{1+1}} \right|-\,\left| \frac{-12}{\sqrt{1+1}} \right|=\frac{4}{\sqrt{2}}\] Length of latus rectum = 4a \[=4\times \frac{4}{\sqrt{2}}=8\sqrt{2}\].You need to login to perform this action.
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