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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The slope of the normal at the point \[(a{{t}^{2}},\ 2at)\] of the parabola \[{{y}^{2}}=4ax\], is            [MNR 1991; UPSEAT 2000]

    A)            \[\frac{1}{t}\]                           

    B)            t

    C)            ?t   

    D)            \[-\frac{1}{t}\]

    Correct Answer: C

    Solution :

               Normal is \[y-2a{{t}_{1}}=\frac{-2at}{2a}(x-a{{t}^{2}})\]            Therefore, slope \[\Rightarrow \].


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