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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The equation of the normal at the point \[\left( \frac{a}{4},\ a \right)\] to the parabola \[{{y}^{2}}=4ax\], is [RPET 1984]

    A)            \[4x+8y+9a=0\]                         

    B)            \[4x+8y-9a=0\]

    C)            \[4x+y-a=0\]                             

    D)            \[4x-y+a=0\]

    Correct Answer: B

    Solution :

               \[x+2y=4.\]                    Þ \[2y+x=2a+\frac{a}{4}=\frac{9a}{4}\]Þ \[2y+x-\frac{9a}{4}=0\]                    i.e., \[4x+8y-9a=0\].


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