A) (4, 4)
B) (9, 6)
C) (4, ?4)
D) (1, ?2)
Correct Answer: D
Solution :
The equation of a normal to \[{{y}^{2}}=4x\]at \[({{m}^{2}},-2m)\] is \[y=mx-2m-{{m}^{3}}.\] If the normal makes equal angles with the coordinates axes, then \[m=\tan \frac{\pi }{4}=1.\] Thus, the required point is (1, ? 2).You need to login to perform this action.
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