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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    In the parabola \[{{y}^{2}}=6x\], the equation of the chord through vertex and negative end of latus rectum, is

    A)            \[y=2x\]                                     

    B)            \[y+2x=0\]

    C)            \[x=2y\]                                     

    D)            \[x+2y=0\]

    Correct Answer: B

    Solution :

               Vertex \[\equiv (0,0).\] End points of latus rectum are\[(a,\,\,\pm \,\,2a)\]. Here \[a=\frac{6}{4}\]            Therefore, \[-ve\]end of latus rectum is \[\left( \frac{3}{2},\,-3 \right)\]            Line through the point is \[y=\frac{-3}{3/2}x\]or \[y+2x=0\].


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