A) {?18, ?12}
B) {?18, 12}
C) {18, 12}
D) (18, ?12)
Correct Answer: D
Solution :
We have \[{{t}_{2}}=-{{t}_{1}}-\frac{2}{{{t}_{1}}}\] Since \[a=2,\,\,{{t}_{1}}=1\]; \[\therefore \] \[{{t}_{2}}=-3\] \[\therefore \]The other end will be \[(at_{2}^{2},\,2a{{t}_{2}})\] i.e., (18, ? 12).You need to login to perform this action.
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