A) \[4al+n=0\]
B) \[4al+4am+n=0\]
C) \[4am+n=0\]
D) \[al+n=0\]
Correct Answer: A
Solution :
The combined equation of the lines joining the vertex to the points of intersection of the line \[lx+my+n=0\] and the parabola \[{{y}^{2}}=4ax\], is \[{{y}^{2}}=4ax\left( \frac{lx+my}{-n} \right)\] or \[4al{{x}^{2}}+4amxy+n{{y}^{2}}=0\] This represents a pair of perpendicular lines, if \[4al+n=0\].
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