A) \[x+3=0\]
B) \[x-3=0\]
C) \[x=1\]
D) \[x+1=0\]
Correct Answer: A
Solution :
Given equation of parabola is \[{{x}^{2}}+6x+20y-51=0\] \[\Rightarrow \]\[{{x}^{2}}+6x=-20y+51\] \[\Rightarrow \]\[{{(x+3)}^{2}}=-20y+60\Rightarrow {{(x+3)}^{2}}=-20(y-3)\] \[\Rightarrow \]\[{{(x+3)}^{2}}=-4.5(y-3)\] \[\therefore \] Axis of parabola is \[x+3=0\].You need to login to perform this action.
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