A) \[y=x\cot \theta +a\tan \theta \]
B) \[x=y\tan \theta +a\cot \theta \]
C) \[y=x\tan \theta +a\cot \theta \]
D) None of these
Correct Answer: C
Solution :
\[m=\tan \theta \]. The tangent to \[{{y}^{2}}=4ax\] is \[y=x\tan \theta +c\] Hence \[c=\frac{a}{\tan \theta }=a\cot \theta \] \ The equation of tangent is \[y=x\tan \theta +a\cot \theta \].You need to login to perform this action.
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