A) (1, 1)
B) \[\left( \frac{1}{2},\ \frac{1}{2} \right)\]
C) (0, 1)
D) (1, 0)
Correct Answer: C
Solution :
m of tangent \[=-1\]. Also from equation of parabola, we get gradient at \[(h,k)\]as the slope of parabola \[=\frac{dy}{dx}=\frac{-1}{2y-1}=\frac{-1}{2k-1}\] Since line and parabola touch at \[(h,k)\] Þ \[\frac{-1}{2k-1}=-1\]Þ\[-2k+1=-1\]Þ\[k=1\] Putting this value in \[x+y=1\], we have \[h=0,\]so the point of contact is \[(0,\,1).\]You need to login to perform this action.
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