A) \[(a{{t}_{1}}{{t}_{2}},\ a({{t}_{1}}+{{t}_{2}}))\]
B) \[(2a{{t}_{1}}{{t}_{2}},\ a({{t}_{1}}+{{t}_{2}}))\]
C) \[(2a{{t}_{1}}{{t}_{2}},\ 2a({{t}_{1}}+{{t}_{2}}))\]
D) None of these
Correct Answer: A
Solution :
Tangents at \['{{t}_{1}}',\,\,\]\['{{t}_{2}}'\] meet at \[(a{{t}_{1}}\,{{t}_{2}},\,a({{t}_{1}}+{{t}_{2}}))\].You need to login to perform this action.
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