A) \[{{x}^{2}}+{{y}^{2}}+30x+12y-27=0\]
B) \[{{x}^{2}}+{{y}^{2}}+30x+12y+27=0\]
C) \[{{x}^{2}}+{{y}^{2}}-30x-12y-27=0\]
D) \[{{x}^{2}}+{{y}^{2}}-30x+12y-27=0\]
Correct Answer: D
Solution :
According to question, equation of circle with points (3, 6) and (27, ?18) on diameter will be \[(x-3)(x-27)+(y-6)(y+18)=0\] \[{{x}^{2}}+{{y}^{2}}-30x+12y-27=0\].
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