JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through the point (6, ?3) is [MP PET 2001]

    A)            \[{{y}^{2}}=12x+6\]                   

    B)            \[{{x}^{2}}=12y\]

    C)            \[{{x}^{2}}=-12y\]                     

    D)            \[{{y}^{2}}=-12x+6\]

    Correct Answer: C

    Solution :

               Since the axis of parabola is y-axis                    \ Equation of parabola \[{{x}^{2}}=4ay\]                    Since it passes through (6, ? 3)                    \ 36 \[=-\,12a\,\,\,\Rightarrow \,a=-3\]                    \ Equation of parabola is \[{{x}^{2}}=-12y\].


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