A) 6
B) 8
C) 10
D) 12
Correct Answer: B
Solution :
Let point be \[(h,k)\]. But \[2h=k,\]then \[{{k}^{2}}=16h\] Þ \[4{{h}^{2}}=16h\]Þ \[h=0,\,h=4\]Þ \[k=0,\,k=8\] \[\] Points are (0,0), (4,8). Hence focal distances are respectively \[0+a=4,\]\[4+4=8\]. \[(\because \,a=4)\]You need to login to perform this action.
You will be redirected in
3 sec